C++ Program to Find Largest Number Among Three Numbers

In this example, you'll learn to find the largest number among three numbers using if, if else and nested if else statements.

To understand this example, you should have the knowledge of following C++ programming topics:

• C++ if, if...else and Nested if...else

In this program, user is asked to enter three numbers.

Then this program finds out the largest number among three numbers entered by user and displays it with proper message. Read More C++

This program can be used in more than one way.

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Example 1: Find Largest Number Using if Statement

#include <iostream>
using namespace std;

int main()
{    
    float n1, n2, n3;

    cout << "Enter three numbers: ";
    cin >> n1 >> n2 >> n3;

    if(n1 >= n2 && n1 >= n3)
    {
        cout << "Largest number: " << n1;
    }

    if(n2 >= n1 && n2 >= n3)
    {
        cout << "Largest number: " << n2;
    }

    if(n3 >= n1 && n3 >= n2) {
        cout << "Largest number: " << n3;
    }

    return 0;
}

Output

Enter three numbers: 2.3
8.3
-4.2
Largest number: 8.3

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Example 2: Find Largest Number Using if...else Statement

#include <iostream>
using namespace std;

int main()
{
    float n1, n2, n3;

    cout << "Enter three numbers: ";
    cin >> n1 >> n2 >> n3;

    if((n1 >= n2) && (n1 >= n3))
        cout << "Largest number: " << n1;
    else if ((n2 >= n1) && (n2 >= n3))
        cout << "Largest number: " << n2;
    else
        cout << "Largest number: " << n3;
    
    return 0;
}

Output

Enter three numbers: 2.3
8.3
-4.2
Largest number: 8.3

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Also Check:

• C++ Program to Print Number Entered by User
• C++ Program to Add Two Numbers
• C++ Program to Find Quotient and Remainder
• C++ Program to Swap Two Numbers
• C++ Program to Check Whether Number is Even or Odd
• C++ Program to Check Whether a character is Vowel or Consonant

Example 3: Find Largest Number Using Nested if...else statement

#include <iostream>
using namespace std;

int main()
{
    float n1, n2, n3;

    cout << "Enter three numbers: ";
    cin >> n1 >> n2 >> n3;

    if (n1 >= n2)
    {
        if (n1 >= n3)
            cout << "Largest number: " << n1;
        else
            cout << "Largest number: " << n3;
    }
    else
    {
        if (n2 >= n3)
            cout << "Largest number: " << n2;
        else
            cout << "Largest number: " << n3;
    }

    return 0;
}

Output

Enter three numbers: 2.3
8.3
-4.2
Largest number: 8.3